Asked on 10/8/2025 by Smith
A 10 kg object is lying on a smooth horizontal surface (no friction). A constant force of 20 N is applied to it. How much distance will the object cover in 5 seconds after the force starts acting?
To solve this problem, we can use the equation of motion, which is: s = ut + (1/2)at^2 where s is the distance covered, u is the initial velocity (which is 0, since the object is initially at rest), t is the time, and a is the acceleration. First, we need to find the acceleration (a) using Newton's second law of motion: F = ma where F is the force (20 N), m is the mass (10 kg), and a is the acceleration. a = F / m = 20 N / 10 kg = 2 m/s^2 Now, we can plug in the values into the equation of motion: s = 0 + (1/2)(2 m/s^2)(5 s)^2 = (1/2)(2 m/s^2)(25 s^2) = 25 m Therefore, the object will cover a distance of 25 meters in 5 seconds after the force starts acting.
Answered on 11/17/2025
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